(x^2-4x-5)/(x^2+3x-4)

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Solution for (x^2-4x-5)/(x^2+3x-4) equation:


D( x )

x^2+3*x-4 = 0

x^2+3*x-4 = 0

x^2+3*x-4 = 0

x^2+3*x-4 = 0

DELTA = 3^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)-3)/(1*2) or x = (-25^(1/2)-3)/(1*2)

x = 1 or x = -4

x in (-oo:-4) U (-4:1) U (1:+oo)

(x^2-(4*x)-5)/(x^2+3*x-4) = 0

(x^2-4*x-5)/(x^2+3*x-4) = 0

x^2-4*x-5 = 0

x^2-4*x-5 = 0

DELTA = (-4)^2-(-5*1*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)+4)/(1*2) or x = (4-36^(1/2))/(1*2)

x = 5 or x = -1

(x+1)*(x-5) = 0

x^2+3*x-4 = 0

x^2+3*x-4 = 0

DELTA = 3^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)-3)/(1*2) or x = (-25^(1/2)-3)/(1*2)

x = 1 or x = -4

(x+4)*(x-1) = 0

((x+1)*(x-5))/((x+4)*(x-1)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -1, 5 }

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